Starter Advanced
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The quickest way to solve the Starter Cube is to get a 3-2 split (3 colored corners on one face and two on the opposite face), once you have that then there are only a few possibilities as shown below. In the two sets of mirror-image configurations, the pair on the left has the misplaced facelet in the top row facing to the left and the pair on the right has it facing to the right.

To match a scrambled 3-2 split cube to one of these first match the top face by placing the cube in the proper position and then twist the bottom face so it also matches (so the misplaced facelets in the bottom row match). The two configurations in each pair are easily distinguished by looking at the bottom face, on the first cube (32A) the two corner facelets are inline and on the second (32B) they are diagonal, use the mouse to view the bottom face on each cube then press Reset and Play to solve.

Left Mirror Right Mirror
32A 32B 32A 32B


The next best way to solve the Starter Cube is to get a 3-1 split. The following shows the possibilities. To match a scrambled 3-1 split cube to one of these the bottom face will need to be twisted but first determine which of the three configurations will match by looking at the locations of the misplaced facelets in the bottom row, if there are two on the same face then it's either 31A or 31C, if not it's 31B. The A & C cubes are distinguished by whether there are two misplaced facelets directly across from each other (on opposite faces), true for A, false for C. Press Play on each cube to solve.

Left Mirror
31A 31B 31C
Right Mirror
31A 31B 31C

On cube 31C above press Reset and then press the Single-Step button (second from right) and use the mouse to rotate the cube horizontally until it matches 31B, that is an alternate way to solve it.

While the above covers the quickest ways to solve the Starter Cube, for the sake of completeness the 3-0 and 3-3 splits are also covered (on the next page) so that every possible configuration with at least three corner facelets on the top face can be solved.